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# Re: [femm] Inductance by means of his definition

- To: femm@yahoogroups.com
- Subject: Re: [femm] Inductance by means of his definition
- From: David Meeker <dmeeker@foster-miller.com>
- Date: Mon, 19 Nov 2001 09:57:40 -0500
- Organization: Foster-Miller, Inc.
- References: <7a.1e0ae307.292a7252@aol.com>

    dcm3c@aol.com wrote:

    > I think that this oughta be:
    >
    > L=(N*h*Scopper/i) * (A1 - A2)
    >
    > where A1 is the average value of a in section Scopper+
    > and A2 is the average value of a in section Scopper-
    >

    Whoops--I meant to say:

    L=(N*h/i) * (A1 - A2)

    The difference in A gives you the flux per unit of length in the
    into-the-page direction that passes through the coil due to current i.
    You have to multiply by h to get the total flux per turn, by N to get
    the total flux for all turns, and divide by i to yield inductance, which
    is a measure of flux linkage per unit of current.

    Dave.

    --------------EF560E49732E92C5430A4378
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    Content-Transfer-Encoding: 7bit

    <!doctype html public "-//w3c//dtd html 4.0 transitional//en">
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    &nbsp;
    <p>dcm3c@aol.com wrote:
    <blockquote TYPE=CITE><font face="Arial"><font color="#000000"><font size=+0>I
    think that this oughta be:</font></font></font>
    <p><font face="Arial"><font color="#000000"><font size=+0>L=(N*h*Scopper/i)
    * (A1 - A2)</font></font></font>
    <p><font face="Arial"><font color="#000000"><font size=-1>where A1 is the
    average value of a in section Scopper+</font></font></font>
    <br><font face="Arial"><font color="#000000"><font size=-1>and A2 is the
    average value of a in section Scopper-</font></font></font>
    <br>&nbsp;</blockquote>
    <font face="Times New Roman,Times">Whoops--I meant to say:</font><font face="Times New Roman,Times"></font>
    <p><font face="Times New Roman,Times"><font color="#000000"><font size=+0>L=(N*h/i)
    * (A1 - A2)</font></font></font><font face="Times New Roman,Times"><font color="#000000"><font size=+0></font></font></font>
    <p><font face="Times New Roman,Times"><font color="#000000"><font size=+0>The
    difference in A gives you the flux per unit of length in the into-the-page
    direction that passes through the coil due to current i.&nbsp; You have
    to multiply by h to get the total flux per turn, by N to get the total
    flux for all turns, and divide by i to yield inductance, which is a measure
    of flux linkage per unit of current.</font></font></font><font face="Times New Roman,Times"><font color="#000000"><font size=+0></font></font></font>
    <p><font face="Times New Roman,Times"><font color="#000000"><font size=+0>Dave.</font></font></font>
    <br><font face="Arial"><font color="#000000"><font size=+0></font></font></font>&nbsp;</html>

    --------------EF560E49732E92C5430A4378--

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    tel;work:781-684-4070
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    url:http://members.aol.com/_ht_a/dcm3c
    org:Foster-Miller, Inc.;Electrical and Electronic Systems Group
    version:2.1
    email;internet:dmeeker@foster-miller.com
    title:Senior Engineer
    adr;quoted-printable:;;350 Second Avenue=0D=0A;Waltham;MA;02451-1196;USA
    fn:David Meeker, Ph.D.
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