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# Re: Bobin (L,R) calculation

- To: femm@yahoogroups.com
- Subject: Re: Bobin (L,R) calculation
- From: "jire602000" <jire@club-internet.fr>
- Date: Sun, 10 Nov 2002 21:47:05 -0000
- In-reply-to: <3DC80CD4.8060503@ieee.org>
- User-agent: eGroups-EW/0.82

    --- In femm@y..., David Meeker <dmeeker@i...> wrote:
    > Thanks for your help !

    I assume the following points . Tell me if I am right or wrong.
    1- The current in circuit or the current density in material is peak
    when AC current is chosen .
    2- So to find the resistance/m is R=W/m *2 / IAC/IAC
    3- So to find the inductance is energy L=*4/IAC/IAC
    4- If axis symmetric is chosen , energy is also the total energy and
    also L=4*W/IAC/IAC

    I have questions on the Litz wire simulation and proxynew.fem
    application.
    1- For this application 1A is in each wire , there is a circuit turnx
    of 1A per wire .The result is 3.180W/m
    If there is one circuit of 100A for 100 wires. Each wire has the same
    turn of 100A. The result is 5.93w/m. I assume that the first case is a
    Litz twisted wire and the second case normal wire composed of 100
    parallel wires . I am OK ?
    Is there any shorter method to apply the 1A in each wire rather than
    having 100 circuits to turn1 up to turn100 ?

    2- The µeff method is a method to replace a Litz wire by a bulk wire.
    Does this work for any place or magnetic field where the Litz wire is
    placed ? what about of proximity effect of Litz wires together ?
    For example, does it mean that if I built an inductance with 2 layers
    of 7 Litz wires of 10*10, it cant be replaced by 2 layers of 7 bulk
    wires . I will then calculate the Hyst losses in the 2*7 bulks + the
    skin effect losses for 2*7*10*10=1400 singles wire of 0.8 and get the
    total equivalent losses ? I am OK ?

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  - Re: [femm] Bobin (L,R) calculation
    - From: David Meeker <dmeeker@ieee.org>

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