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# PMsquare dead end...

- To: femm@yahoogroups.com
- Subject: PMsquare dead end...
- From: harti@harti.com
- Date: Wed, 13 Jun 2001 20:05:15 -0000
- In-reply-to: <3B27BF6F.CCC2E45F@foster-miller.com>
- User-agent: eGroups-EW/0.82

    Hi All,
    thanks a lot for all your help.
    I see now, that the PMSquare as suggested
    is a "dead horse".
    It seems only to generate horizontal forces
    due to the end conditions of the stator magnets....
    It is also too complicated to be build for a real
    linear motor.
    Thus I am working now on a kind of Howard Johnson
    like linear magnet motor, where the runner magnet
    flies over a track of steel plates.
    So the difference to the Howard Johnson design is,
    that the stator track does not use any magnets but just steel
    plates. The runner magnet above it uses special core pieces
    so the magnet never locks in any position, but always
    wants to move on to the side.
    It just depends on the steel plate spacings versus air gaps
    versus runner magnet dimension.

    I am trying now to find the right dimensions, so that there is
    always a positive force into the x-direction.

    Regards, Stefan.

    --- In femm@y..., David Meeker <dmeeker@f...> wrote:
    >
    >
    > Dave Squires wrote:
    >
    > > David,
    > > I don't think I quite agree with your explanation.
    > > If the two magnets are locked together and held
    > > in the position shown you then have a
    > >
    > > Net force = +B*Q +(-B*Q) = 0
    > >
    > > if embedded in a uniform field. Isn't that correct?
    > >
    > > Dave Squires
    >
    > That's exactly right--there is no net force on a permanent magnet
    in a uniform
    > field.
    >
    > Dave.

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