[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

# Re: Calculation of self and mutual inductances

- To: femm@egroups.com
- Subject: Re: Calculation of self and mutual inductances
- From: "Rob " <rtickle@visi.com>
- Date: Fri, 29 Dec 2000 08:06:00 -0000
- In-reply-to: <92fgql+pf9f@eGroups.com>
- User-agent: eGroups-EW/0.82

    --- In femm@egroups.com, P.Neumaier@z... wrote:
    > Hello,
    >
    > can anybody help me? When I calculate the self inductance of e.g. a
    > coil encircling a copper rod using the "A.J" integral I get the
    > correct unit "Henry * A²". But this integral yields incorrect
    > results, which can be prooved when defining a problem, which can
    also
    > be solved analytically. However, using the integral "A" for the
    > mutual inductance, the value is correct, but the unit is given
    > as "A*m³" which is obviously not the unit for an inductance.
    >
    > Thanks for any answer in advance.
    >
    > Peter

    Are you dividing the result FEMM gives you by the current in the coil
    squared? If so are you using the correct value for the current? If
    you have multiple turns the current scales with N... I did some
    calculations like this when I started using FEMM and got some
    incorrect answers due to faulty current values. Be sure to add up all
    cross sectional areas of conductor multiplied by their respective
    current densities. This solved the problems I was having...

- Follow-Ups:
  - Re: Calculation of self and mutual inductances
    - From: "Rob " <rtickle@visi.com>

- References:
  - Calculation of self and mutual inductances
    - From: P.Neumaier@z.zgs.de

- Prev by Date: Calculation of self and mutual inductances
- Next by Date: Inductance and mutul inductance caculation
- Previous by thread: Calculation of self and mutual inductances
- Next by thread: Re: Calculation of self and mutual inductances
- Index(es):
  - Date
  - Thread