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# Re: [femm] Re: inductance - parallel strips

- To: femm@yahoogroups.com
- Subject: Re: [femm] Re: inductance - parallel strips
- From: "Jim in_Dallas" <jim271@hotmail.com>
- Date: Wed, 14 Nov 2001 17:07:03 -0600
- Bcc:

`Hello Tomislav,`
`This is interesting.`

    I get L=523nH/m using FEMM, which is about 1/2 what the formula gives.
    There is a web site with a similar formula for this configuration:
    http://emclab.umr.edu/new-induct/trace-v.html

`Using their interactive form, I get L=1028nH/m.`
`Maybe someone can explain why we get a different result with FEMM?`

    Regards,
    Jim
    ==============================================

>     From: tborzic@yahoo.com
>     Reply-To: femm@yahoogroups.com
>     To: femm@yahoogroups.com
>     Subject: [femm] Re: inductance - revised axisymmetric model
>     Date: Wed, 14 Nov 2001 19:47:04 -0000

>     thanx Jim, I hope that will do with The Professor.
>     I have one more question..

>     As you may see, inductance is generally my problem.
>     Currently i am trying to solve inductance between
>     two reactangular conductors, infinite lenghth, paralell.
>     they are standing like this - II.
>     Numerically, inductance for such case is:

> `L=(2*mi0/h)*(b+a/3)`

>     where h-heighth,2b distance between conductors (not
>     between theirs centers), and a width.
>     so if a=0.2cm, b=0.8cm (2b = distance 1.6cm),h=2.2cm
>     L=9.89 e-7 H/m, while femm allways returns half of that value.
>     I applied 1A current for easier computing.
>     so, where is mistake?
>     thanks
>     tomislav

``

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Attachment: `parallel2.FEM`
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