I get L=523nH/m using FEMM, which is about 1/2 what the formula gives. There is a web site with a similar formula for this configuration: http://emclab.umr.edu/new-induct/trace-v.html
Regards, Jim ==============================================
From: tborzic@xxxxxxxxx Reply-To: femm@xxxxxxxxxxxxxxx To: femm@xxxxxxxxxxxxxxx Subject: [femm] Re: inductance - revised axisymmetric model Date: Wed, 14 Nov 2001 19:47:04 -0000
thanx Jim, I hope that will do with The Professor. I have one more question..
As you may see, inductance is generally my problem. Currently i am trying to solve inductance between two reactangular conductors, infinite lenghth, paralell. they are standing like this - II. Numerically, inductance for such case is:
L=(2*mi0/h)*(b+a/3)
where h-heighth,2b distance between conductors (not between theirs centers), and a width. so if a=0.2cm, b=0.8cm (2b = distance 1.6cm),h=2.2cm L=9.89 e-7 H/m, while femm allways returns half of that value. I applied 1A current for easier computing. so, where is mistake? thanks tomislav
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