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[FEMM] (no subject)



Hi, everyone.
Dear Dr. David Meeker.

By the program FEMM it is now posible to calculate
electrostatics or magnetics problems.
The program calculate with a COIL-INTENSITY (A) as INPUT. As
results are, par example:

Total current = 13052.1 - j 74325.1 Amps  (AMPLITUDE)
Voltage Drop = 71.0381 + j 0.107124 Volts  (AMPLITUDE)
Flux Linkage = 0.0385309 - j 0.219415 Webers
Flux/Current = 2.95209e-006 - j 1.05879e-022 Henries
Voltage/Current = 0.000161422 + j 0.000927428 Ohms
Real Power = 459616 Watts
Reactive Power = 2.64066e+006 VAr
Apparent Power = 2.68036e+006 VA

Well, but for Time Harmonic Magnetic Problems, i think it is
better to calculate
with the COIL-VOLTAGE -par example =1000.0+j0.0 (as efectiv, not
amplitude).
I propose, the programm calculate internal with
V=1000*sqrt(2)Volt(as amplitude, if necesary!!) and with a
Coil-Current=1 A (par example), calculate internal the new
Voltage Drop and with some Iterations calculate a new
Coil-Current and a new Voltage Drop,etc, until the condition:

     ABS(New Voltage Drop/COIL-VOLTAGE=1000.0*sqrt(2)-1)LT.1E-6

For FEMM that is very easy!

For Time Harmonic Magnetic ProblemsThe i think it is better the
results as "efectiv"
and not as AMPLITUDE.

Thanks

Santiago Salamanca