|
Thanks Mr. Meeker for the comprehensive
explanation. Now I have the following question: We have two methods to calculate
inductance:
1) using the integral of A.J over the current
carrying coils:
Results: integral of A.J = [(8.31e-4)
-(j7.99e-6)] Henry Amp^2
current=225 Amper-Turn
gives an inductance of L=[(3.69 e-6)- (j3.55 e-8)]
Henry
2) using the integral of magnetic energy.
integral of magnetic field energy over thewhole
area (instead of current carrying components)=2.081 e-4 joule
current=225 Amper-Turn
gives an inductance of L=[1.849
e-6] Henry
Now ignoring the imaginary part of the first
solution (so the eddy currents and the hysteresis losses) which one should
be taken as the inductance? 3.69 mH or 1.84 mH? Thanks in
advance.
|